(Due Date: Wednesday 2, June)

In this homework you will implement the following procedures:

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* sreverse

  Here sreverse stands for super-reverse. Given a list of lists sreverse
will reverse the outer list as well as it reverses the sub-lists.
  Here are some examples about how sreverse works:

?- sreverse([[1,2,3,4]],RL1).

RL1 = [[4,3,2,1]] ?

yes
?- sreverse([[1,2,3],[4,5,6]],RL2).

RL2 = [[6,5,4],[3,2,1]] ?

yes
?- sreverse([[a,b],[c,d],[e,f]],RL3).

RL3 = [[f,e],[d,c],[b,a]] ?

yes

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* flatten

  flatten will take a list of lists and will create just one list,
whose members are the members of the sub-lists.

  Here are some examples about how flatten works:

?- flatten([[1,2,3,4]], FL1).

FL1 = [1,2,3,4] ?

yes
?- flatten([[1,2,3],[4,5,6]], FL2).

FL2 = [1,2,3,4,5,6] ?

yes
?- flatten([[a,b],[c,d],[e,f]], FL3).

FL3 = [a,b,c,d,e,f] ?

yes

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* sdelete

  Here sdelete stands for super-delete. Given a list of lists, and a member
sdelete will delete all occurences of that member in the sublists.
  Here are some examples about how sdelete works.

?- sdelete([[1,2],[3,4]], 2, DL1).

DL1 = [[1],[3,4]] ?

yes
?- sdelete([[1,2],[1,3],[1,4]], 1, DL2).

DL2 = [[2],[3],[4]] ?

yes
?- sdelete([[a,a,b,b,c,c,d,d]], b, DL3).

DL3 = [[a,a,c,c,d,d]] ?

yes

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* sublist

  Given two lists sublist will seek for an occurence of its first argument in
its second argument. 
  Here are some examples about how sublist works:

?- sublist([1,2,3],[1,2,3,4,5]).

yes
?- sublist([c,d],[a,b,c,d]).

yes
?- sublist([a,b],[a,d,g]).

no